Originally Posted by
Fuel Fire Desire
I’m doing some basic high school math. I’m curious what peak frame stress my revolver is encountering during firing (just for fun).
The .454 Casull produces 53,000 psi.
The .454 Casull bullet is 0.452”
Pi x r squared is 0.16 square inches of area.
53,000 psi x 0.16 square inches is 8,480 ponds of force.
Is my math correct on thinking that the frame of my revolver is withstanding 4.24 tons of stretching force upon firing? Just bored and curious. Pretty impressive as well.